Easier Done Than Said?

题目:给你一个小写字符串,判断是否安全,,安全规则如下:

1.包含元音字母;2.相邻3个元素不能都是元音或辅音;3.连续2个字母相同之能是o或e。

分析:简单题。直接模拟即可。

说明:今天有点累╮(╯▽╰)╭,要学的东西好多( ⊙ o ⊙ )啊!

#include <algorithm>#include <iostream>#include <cstdlib>#include <cstring>#include <cstdio>#include <cmath>using namespace std;int f(char c){return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');}char buf[32];int main(){while (gets(buf) && strcmp(buf, "end")) {int flag = 0;for (int i = 0 ; buf[i] ; ++ i)if (f(buf[i]))flag = 1;for (int i = 2 ; buf[i] ; ++ i) {if (f(buf[i])&&f(buf[i-1])&&f(buf[i-2]))flag = 0;if (!f(buf[i])&&!f(buf[i-1])&&!f(buf[i-2]))flag = 0;}for (int i = 1 ; buf[i] ; ++ i)if (buf[i] == buf[i-1] && buf[i] != 'e' && buf[i] != 'o')flag = 0;if (flag) printf("<%s> is acceptable.\n",buf);else printf("<%s> is not acceptable.\n",buf);}return 0;}

生命有限,努力无限

Easier Done Than Said?

相关文章:

你感兴趣的文章:

标签云: