从Matrix67 blog里面看到了Tweetable Mathematical Art。
使用C++实现3个函数RD(i, j), GR(i, j), BL(i, j)分别返回像素(i, j)的R/G/B值，最终生成1幅1024*1024的图片。要求是每个函数代码不超过140字符，即Tweetable。
来个太极八卦图，，娱乐一下。
unsigned char RD(int i,int j){// YOUR CODE HERE#define LEFT (i < DIM/2)#define C1 C(DIM/2, DIM/2, DIM/2)#define C2 C(DIM/2, DIM/4, DIM/4)return BL(i, j);}unsigned char GR(int i,int j){// YOUR CODE HERE#define C3 C(DIM/2, 3*DIM/4, DIM/4)#define C4 C(DIM/2, DIM/4, DIM/16)#define C5 C(DIM/2, 3*DIM/4, DIM/16)return BL(i, j);}unsigned char BL(int i,int j){// YOUR CODE HERE#define C(x, y, r) (_sq(i – (x)) + _sq(j – (y)) < _sq((r)))return !C1 ? 127 : C2 ? C4 ? 255 : 0 : C3 ? C5 ? 0: 255 : LEFT ? 0 :255;} unsigned char RD(int i,int j){#define r(n)(rand()%n)static char c[1024][1024];return!c[i][j]?c[i][j]=!r(999)?r(256):RD((i+r(2))%1024,(j+r(2))%1024):c[i][j];}生成图片
知已知彼，百战百胜。
