Why is celsius = 5 * (fahr

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There is a program to print Fahrenheit-Celsius table as below.

#include <stdio.h>/* print Fahrenheit-Celsius tablefor fahr = 0, 20, …, 300 */int main(){int fahr, celsius;int lower, upper, step;lower = 0; /* lower limit of temperature table */upper = 300; /* upper limit */step = 20; /* step size */fahr = lower;while (fahr <= upper) {celsius = 5 * (fahr – 32) / 9;printf("%d\t%d\n", fahr, celsius);fahr = fahr + step;}}

The right part of the figure is the output of this program. The Celsius temperature is computed and assigned to the variablecelsiusby the statement

celsius = 5 * (fahr – 32) / 9;

The reason for multiplying by 5 and then dividing by 9 instead of just multiplying by 5/9 is that in C, as in many other languages,integer division truncates: any fractional part is discarded. Since 5 and 9 are integers, 5/9 would be truncated to zero and so all the Celsius temperatures would be reported as zero.

Reference

The C Programming Language

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Why is celsius = 5 * (fahr

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