题目
题目很简单，就是写一个函数把string转换成int，但是通过率只有可怜的11%，难点是要考虑所有情况，，特别是int溢出边界，反正我是写了2个小时还没解决，先放到这，有空接着搞，现在应该还有最后一个bug。
Implementatoito convert a string to an integer.
Hint:Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes:It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
代码
public class Solution {public int atoi(String str) {String num_str="";char[] str_char=str.toCharArray();char[] sympo="-+".toCharArray();boolean abs=true;for(int i=0;i<str.length();i++){if(str_char[i]==sympo[0] ||str_char[i]==sympo[1]){if(!Character.isDigit(str_char[i+1])){return 0;}if(str_char[i]==sympo[0]){abs=false;}}if(Character.isDigit(str_char[i])){num_str+=String.valueOf(str_char[i]);}else{if(num_str.length()!=0){break;}}//if(Character.isDigit(str_char[i])){//num_str+=String.valueOf(str_char[i]);//}if(num_str!=""){if(Math.abs(Integer.parseInt(num_str))>=Integer.MAX_VALUE / 10){return Integer.MAX_VALUE;}}}if(num_str!=""){if(abs){return Integer.parseInt(num_str);}else{return -Integer.parseInt(num_str);}}else{return 0;}}}
代码下载：https://github.com/jimenbian/GarvinLeetCode
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接受失败更是一种智者的宣言和呐喊
