Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
class Solution {public:vector<int> Num;TreeNode *sortedArrayToBST(vector<int> &num) {if (num.size() == 0) return NULL;Num = num;return make(0, Num.size() – 1);}TreeNode * make(int l, int r) {int mid = (l + r) / 2;TreeNode * newRoot = new TreeNode(Num[mid]);if (l < mid) newRoot->left = make(l, mid – 1);if (mid < r) newRoot->right = make(mid + 1, r);return newRoot;}};
,我躺下来,以一张报纸当枕头。高高在我上方的,