问题的提出：编写程序实现子女随父亲（或母亲）姓，，要求显示子女的姓名和年龄及其父母亲的姓名和年龄，其中子女的姓氏要求同父亲的姓氏。
输入：父母的姓名，年龄，孩子的名字，年龄。
输出：父母的姓名，年龄，孩子的姓名，年龄。
使用类的继承来完成。
代码：
// test14.cpp : 定义控制台应用程序的入口点。//#include "stdafx.h"#include <iostream>#include <string>using namespace std;class Father{protected:char* surname;char* name;int age;public:Father(){cout<<"Father 的默认构造函数调用！"<<endl;surname=NULL;name=NULL;}Father(char *fn, char *n, int num){cout<<"Father 构造函数"<<endl;surname=new char[strlen(fn)+1];strcpy(surname,fn);name=new char[strlen(n)+1];strcpy(name,n);age=num;}~Father(){cout<<"Father的析构函数！"<<endl;delete surname;delete name;}char *getSurname(){return surname;}void disp(){cout<<"姓名: "<<surname<<name<<endl;cout<<"年龄: "<<age<<endl;}};class Mother{protected:char* surname;char* name;int age;public:Mother(){cout<<"Mother 的默认构造函数调用！"<<endl;surname=NULL;name=NULL;}Mother(char *fn, char *n, int num){cout<<"Mother 构造函数"<<endl;surname=new char[strlen(fn)+1];strcpy(surname,fn);name=new char[strlen(n)+1];strcpy(name,n);age=num;}~Mother(){cout<<"Mother的析构函数！"<<endl;delete surname;delete name;}void disp(){cout<<"姓名: "<<surname<<name<<endl;cout<<"年龄: "<<age<<"岁"<<endl;}};//继承class Child:public Father, public Mother{private:Father *myfather;Mother *mymother;public:Child(){cout<<"Child 默认构造函数"<<endl;}Child(Father &mf, Mother &mm, int n, char *name):myfather(&mf),mymother(&mm){cout<<"Child 构造函数"<<endl;Mother::surname=new char[strlen(mf.getSurname())+1];//不能省略Mother::，否则出现二义性strcpy(Mother::surname, mf.getSurname());Mother::name=new char[strlen(name)+1];strcpy(Mother::name, name);Mother::age=n;}void disp(){Mother::disp();cout<<"父亲： "<<endl;myfather->disp();cout<<"母亲： "<<endl;mymother->disp();cout<<endl;}~Child(){delete Mother::surname;delete Mother::name;}};int _tmain(int argc, _TCHAR* argv[]){Father mf1("张","超",40), mf2("王","海波",50);Mother mm1("刘","亦菲",35), mm2("张","靓颖",53);Child cc(mf1, mm1, 18, "明明");Child dd(mf2, mm2, 17, "小华");cout<<"两家人："<<endl;cc.disp();dd.disp();system("pause");return 0;}结果：
喜欢就喜欢了，心被牵动，无须理由，爱上你是我的自由，
