【思路】：按照题意来就行。注意当p1=2时，，字母串和数字串的区别。推荐使用string，采用replace函数替换就行，char[]移动大量数据。
【AC代码】：
#include <iostream>#include <algorithm>#include <string>#include <cstdio>#include <cstring>using namespace std;#define MAX 10000+5int isLower(char c){if (c >= 'a' && c <= 'z')return 1;return 0;}int isNum(char c){if (c >= '0' && c <= '9')return 1;return 0;}void reverse(char repstr[]){int i = 0;for (i = 0; i < strlen(repstr)/2; i++){char temp;temp = repstr[i];repstr[i] = repstr[strlen(repstr)-1-i];repstr[strlen(repstr)-1-i] = temp;}}int main(){freopen("in.txt", "r", stdin);freopen("out.txt", "w", stdout);int p1 = 0, p2 = 0, p3 = 0, i = 0, j = 0, k = 0;string str;//inputcin >> p1 >> p2 >> p3;cin >> str;//handlefor (i = 1; i < str.length()-1; i++) //注意范围 {if ('-' == str[i]){int flag = 0;char repstr[MAX];if (isLower(str[i-1]) && isLower(str[i+1]) && str[i+1]>str[i-1])flag = 1;else if (isNum(str[i-1]) && isNum(str[i+1]) && str[i+1]>str[i-1])flag = 2;if (0==flag)continue;//replace p1 p2int cnt = 0;for (j = str[i-1]+1; j < str[i+1]; j++){for (k = 0; k < p2; k++){if (1 == p1){repstr[cnt++] = j;}else if (2 == p1){if (1 == flag)repstr[cnt++] = j+'A'-'a';else if (2 == flag)repstr[cnt++] = j;}else if (3 == p1){repstr[cnt++] = '*';}}}repstr[cnt] = '\0';//p3if (2 == p3)reverse(repstr);//replacestring rep = repstr;str.replace(i, 1, rep);}}//outputcout << str;return 0;}
备注：
1.C++string类常用函数
2.string 与char* char[]之间的转换
累死累活不说，走马观花反而少了真实体验，
