[LeetCode 11]Container With Most Water

题目链接:container-with-most-water

/** * Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.Note: You may not slant the container. * */public class ContainerWithMostWater {//45 / 45 test cases passed.//Status: Accepted//Runtime: 256 ms//Submitted: 0 minutes ago//时间复杂度O(n) 空间复杂度O(1)static int maxArea(int[] height) {int left = 0;int right = height.length – 1;int max = 0;while(left < right) {int area = Math.min(height[left], height[right]) * (right – left);max = Math.max(max, area);if(height[left] <= height[right]) {left ++;} else {right — ;}}return max;}public static void main(String[] args) {System.out.println(maxArea(new int[]{2, 0, 2}));}}

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[LeetCode 11]Container With Most Water

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