2.29#include<iostream>using namespace std;const int n=20;int Fbi(int i,int j){int t;t=i+j;return t;}int main(){int *p,a;p=new int[n];p[0]=1;p[1]=1;for(a=2;a<n;a++){p[a]=Fbi(p[a-1],p[a-2]);}cout<<"output Fbionacci的前20项：";for(a=0;a<n;a++){cout<<p[a]<<" ";}cout<<endl;delete p;return 0;}2.30
#include<iostream>#include<cmath>using namespace std;int sroot(int a){return sqrt(a);}long sroot(long b){return sqrt(b);}double sroot(double c){return sqrt(c);}int main(){int i,t;long j,l;double k,h;cout<<"请依次输入一个整数、长整数与双精度数：";cin>>i>>j>>k;t=sroot(i);l=sroot(j);h=sroot(k);cout<<"这三个数的二次方根依次为："<<t<<" "<<l<<" "<<h<<endl;return 0;}
，相信梦想是价值的源泉，相信眼光决定未来的一切，
