POJ 2533 Longest Ordered Subsequence (模版LIS)

题意:输出最长递增子序列的长度思路:直接裸LIS,</pre><pre code_snippet_id="648389" snippet_file_name="blog_20150420_4_7842089" class="sio" name="code" style="white-space: pre-wrap; word-wrap: break-word; font-size: 14px; line-height: 26px; background-color: rgb(255, 255, 255);"><pre name="code" class="cpp">#include<cstdio>const int N = 1001;int a[N], f[N], d[N]; // d[i]用于记录a[0…i]的最大长度int bsearch(const int *f, int size, const int &a) {int l=0, r=size-1;while( l <= r ){int mid = (l+r)/2;if( a > f[mid-1] && a <= f[mid] ) return mid;// >&&<= 换为: >= && <else if( a < f[mid] ) r = mid-1;else l = mid+1;}}int LIS(const int *a, const int &n){int i, j, size = 1;f[0] = a[0]; d[0] = 1;for( i=1; i < n; ++i ){if( a[i] <= f[0] ) j = 0; // <= 换为: <else if( a[i] > f[size-1] ) j = size++;// > 换为: >=else j = bsearch(f, size, a[i]);f[j] = a[i]; d[i] = j+1;}return size;}int main(){int i, n;while( scanf("%d",&n) != EOF ){for( i=0; i < n; ++i ) scanf("%d", &a[i]);printf("%d\n", LIS(a, n)); // 求最大递增/上升子序列(如果为最大非降子序列,只需把上面的注释部分给与替换)}return 0;}

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POJ 2533 Longest Ordered Subsequence (模版LIS)

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