【LeetCode从零单刷】Maximum Subarray

题目:

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array[2,1,3,4,1,2,1,5,4], the contiguous subarray[4,1,2,1]has the largest sum =6.

解答:

简单的动态规划。判断以前所有的努力是否对 当前元素 有正影响。

class Solution {public:int maxSubArray(vector<int>& nums) {if(nums.size() == 1){return nums[0];}int* dp = new int[nums.size()];dp[0] = nums[0];int max = dp[0];for(int i = 1; i < nums.size(); i++){if(dp[i-1] + nums[i] > nums[i]){dp[i] = dp[i-1] + nums[i];if(max < dp[i]) max = dp[i];}else{dp[i] = nums[i];if(max < dp[i]) max = dp[i];}}return max;}};

,然后拍一些美得想哭的照片,留给老年的自己。

【LeetCode从零单刷】Maximum Subarray

相关文章:

你感兴趣的文章:

标签云: