IBM 3624 Customer PIN,Natural PIN,PIN Offset的相关内容以下描述了利用IBM 3624产生k位用户pin的方法1.用PIN Verification Key (PVK)加密PAN（Primary Account Number）最右16位，产生16位十六进制字符串；2.利用Decimalisation Table = 0123456789012345，将第1步结果转换为10机制数，例如：HEX0 1 2 3 4 5 6 7 8 9 A B C D E FDECIMAL0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 53. 取第2步结果的前k位，即可得到k为Natural PIN4. Natural PIN加上PIN Offset值就得到了Customer PIN（注意：位加不进位，，即：no-carry-addition）；5. 相反PIN Offset为Customer PIN减去Natural PIN（注意：位减不借位，即：no-borrows-subtraction）.Examples 1:Account:1234567890123456PVK:1313131313131313Decimalisation Table: 0123456789012345 , ie. 0(Hex) = 0, B(Hex) = 1, etc.PIN length:k=6Then the result of step 1 =64DA85B3795AE4E4Result of step 2 =6430851379504444 (decimal)Then Natural PIN =643085(1) Let PIN Offset be456789Customer PIN=643085 + 456789 (no carry-over on each digit) = 099764(2) Let PIN Offset be000000Customer PIN=643085 + 000000 (no carry-over on each digit) = 643085Examples 2:Card number: 1234567890123445PIN key: 0123456789ABCDEFEncrypted card number: 9A466AD30DFE0381Natural PIN: 9046.Offset: 2298 (this number is written on track 3).Customer PIN: 1234.PIN Offset通常写在第三磁道参考文档：~padilla/extrawork/magexam1.html%23wq3968
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