LeetCode — Bitwise AND of Numbers Range

题目描述：Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.For example, given the range [5, 7], you should return 4.就是对从m到n之间的数字做与运算。思路：本题的关键在于，求出了n& n-1为v，就可以直接把n设为v，而没必要在求v与n-1之间的数了。实现代码：public class Solution {public int RangeBitwiseAnd(int m, int n){while(n > m){n = n & n-1;}return n & m ;}}

送给中意的TA，背面写上：某年某月某日，