C语言代码实现井字棋游戏

井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“#”棋子,谁先连成3个,谁就赢。

本次使用C语言来实现这个小游戏。

由于使用函数较多,所以采用多文件的方式方便梳理代码思路。

本次一共有三个文件:

**

game.h:

包含了game.c文件中函数的声明和库函数的声明。**

#pragma once#define ROW 3#define COL 3#include<stdio.h>#include<stdlib.h>#include<time.h>void InitBoard(char board [ROW][COL], int row, int col); //初始化棋盘void DisplayBoard(char board [ROW][COL], int row, int col); //打印棋盘void PlayerBoard(char board [ROW][COL], int row, int col); //玩家走void ComputerBoard(char board [ROW][COL], int row, int col);//电脑走char IsWin(char board [ROW][COL], int row, int col); //结果判断

game.c:

包含游戏过程中关键函数的函数主体。

#define _CRT_SECURE_NO_WARNINGS#include"game.h"void InitBoard(char board[ROW][COL], int row, int col){ //初始化棋盘 int i = 0; for (i = 0; i < row; i++) {  int j = 0;  for (j = 0; j < col; j++)   board [i][j] = ' '; }}void DisplayBoard(char board [ROW][COL], int row, int col){ //打印棋盘 int i = 0; for (i = 0; i < row; i++) {  int j = 0;  for (j = 0; j < col; j++)  {   printf(" %c ", board [i][j]);   if (j < col - 1)    printf("|");  }  printf("\n");  if (i < row - 1)  {   for (j = 0; j < col; j++)   {    printf("---");    if (j < col - 1)     printf("|");   }   printf("\n");  } }}void PlayerBoard(char board [ROW][COL], int row, int col){ int x = 0, y = 0; while (1) {  printf("输入棋子坐标->");  scanf("%d%d", &x, &y);  if (x > 0 && x <= row && y > 0 && y <= col)  {   if (board [x - 1][y - 1] == ' ')   {    board [x - 1][y - 1] = '*';    break;   }   else   {    printf("此位置已有棋子!请重新输入。\n");   }  }  else  {   printf("输入错误!请重新输入。\n");  } }}void ComputerBoard(char board [ROW][COL], int row, int col){ int x = 0, y = 0; while (1) {  x = rand() % row;  y = rand() % col;  if (board [x][y] != ' ')  {   continue;  }  else  {   board [x][y] = '#';   break;  } }}int IsFull(char board [ROW][COL], int row, int col){ int i = 0; for (i = 0; i < row; i++) {  int j = 0;  for (j = 0; j < col; j++)  {   if (board [i][j] == ' ')    return 0;  } } return 1;}char IsWin(char board [ROW][COL], int row, int col){ int i = 0; //行 for (i = 0; i < row; i++) {  if (board [i][0] == board [i][1] && board [i][1] == board [i][2] && board [i][0] != ' ')   return board [i][0]; } //列 for (i = 0; i < col; i++) {  if (board [0][i] == board [1][i] && board [1][i] == board [2][i] && board [0][i] != ' ')   return board [0][i]; } //对角线 if (board [0][0] == board [1][1] && board [1][1] == board [2][2] & board [1][1] != ' ')  return board [1][1]; if (board [2][0] == board [1][1] && board [1][1] == board [0][2] & board [1][1] != ' ')  return board [1][1]; //是否平局 if (IsFull(board, row, col))  return 'Q';//平局 return 'C';//继续}

test.c:

main函数和游戏的大概流程。

#define _CRT_SECURE_NO_WARNINGS#include"game.h"void Menu(){ printf("*******************************\n"); printf("**********  1、play  **********\n"); printf("**********  0、quit  **********\n"); printf("*******************************\n");}void game(){ char board [ROW][COL]; InitBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); char ret = 0; srand((unsigned int) time(NULL)); while (1) {  printf("玩家走\n");  PlayerBoard(board, ROW, COL);  DisplayBoard(board, ROW, COL);  ret = IsWin(board, ROW, COL);  if (ret != 'C')   break;     printf("电脑走\n");  ComputerBoard(board, ROW, COL);  DisplayBoard(board, ROW, COL);  ret = IsWin(board, ROW, COL);  if (ret != 'C')   break; } if (ret == '*')  printf("玩家胜利!\n"); else if (ret == '#')  printf("电脑胜利!\n"); else  printf("平局!\n");}int main(){ //三子棋 int input = 1; while (input) {  Menu();  printf("输入1开始游戏,输入0退出游戏。\n请输入->");  scanf("%d", &input);  switch(input)  {   case 1:    game();    printf("开始游戏\n");    break;   case 0:    printf("游戏结束\n");    break;   default:    printf("非法输入,请重试!\n");  }   } return 0;}

运行图片

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C语言代码实现井字棋游戏

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