nyoj 4 ASCII码排序 java

java输入字符:1、String s=sc.next();

2、char a=s.charAt(0);

注意:package java 中提交不能带package

java代码:

java.util.Scanner; Main { main(String[] args) 9 {10Scanner input = new Scanner(System.in);11int n = input.nextInt();12while(n–>0)13 {14String string = input.next();15char a = string.charAt(0);16char b = string.charAt(1);17char c = string.charAt(2);(a>b){char s=a;a=b;b=s;}20if(a>c){char s=a;a=c;c=s;}21if(b>c){char s=b;b=c;c=s;}2223System.out.println(a+” “+b+” “+c);24 }2526 }27 },其实你已经错过了旅行的意义。

nyoj 4 ASCII码排序 java

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