如果gridview导出excel文件时，这个文件名是存在且处于打开状态时怎么处理？
下面是一段excel导出的程序：
private void buttonExcle_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog = new SaveFileDialog();
DfWeb web = new DfWeb(new P101001Service(), this);
P101001DataSet dset = (P101001DataSet)web.Execute(“GetDayListBySearch”);
_griddata = dset.DayList;
dfDataGridView1.DataSource = _griddata;
saveFileDialog.Filter = “Execl files (*.xls)|*.xls”;
saveFileDialog.FilterIndex = 0;
saveFileDialog.RestoreDirectory = true;
saveFileDialog.CreatePrompt = true;
saveFileDialog.Title = “Export Excel File To”;
if (saveFileDialog.ShowDialog() == DialogResult.Cancel)
{
return;
}
Stream myStream;
myStream = saveFileDialog.OpenFile();
StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(“gb2312”));
StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(-0));
string str = “”;
try
{
for (int i = 0; i < dfDataGridView1.ColumnCount; i++)
{
if (i > 0)
{
str += “\t”;
}
str += dfDataGridView1.Columns[i].HeaderText;
}
sw.WriteLine(str);
写内容
for (int j = 0; j < dfDataGridView1.Rows.Count; j++)
{
string tempStr = “”;
for (int k = 0; k < dfDataGridView1.Columns.Count; k++)
{
if (k > 0)
{
tempStr += “\t”;
}
object value = dfDataGridView1.Rows[j].Cells[k].Value;
if (value == null)
{
value = string.Empty;
}
tempStr += value.ToString();
}
sw.WriteLine(tempStr);
}
sw.Close();
myStream.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
finally
{
sw.Close();
myStream.Close();
}
}
如果gridview导出excel文件时，这个文件名是存在且处于打开状态时怎么处理？如果不处理，程序将会崩溃。
求各位大侠鼎力帮助。
你将if (saveFileDialog.ShowDialog() == DialogResult.Cancel)
{
return;
}
Stream myStream;
myStream = saveFileDialog.OpenFile();
StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(“gb2312&qu
