一道编程题实在是不知道哪个地方错了

一道觉得很简单的编程题,提交了很多次,,但是,还是wrong,实在是崩溃啊,真的不知道哪里错了,希望大家可以帮忙解决一下,感激不尽。就是这道题————Conversions

Description

Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

Input

The first line of input contains a single integerN, (1 <= N <= 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

Output

For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

Sample Input

51 kg2 l7 lb3.5 g0 l

Sample Output

1 2.2046 lb2 0.5284 g3 3.1752 kg4 13.2489 l5 0.0000 g下面是我的代码,求帮忙#include<stdio.h>#include <string.h> int main(){int n, i, count;char a[1001];double result, x;while(~scanf("%d", &n)){for(i=0;i<n;i++){scanf("%lf %s", &x, a);if(strcmp(a, "kg")==0){result=2.2046*x;printf("%d %.4f lb\n", i+1, result);}else if(strcmp(a, "lb")==0){result=0.4536*x;printf("%d %.4f kg\n", i+1, result);}else if(strcmp(a, "l")==0){result=0.2642*x;printf("%d %.4f g\n", i+1, result);}else if(strcmp(a, "g")==0){result=3.7854*x;printf("%d %.4f l\n", i+1, result);}}}return 0;}希望大家可以帮帮忙,先谢谢了。

对于沙漠中的旅行者,最可怕的不是眼前无尽的荒漠,而是心中没有绿洲。

一道编程题实在是不知道哪个地方错了

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