Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.
Input Specification:
The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).
Sample Input:31 2 32 3 49223372036854775807 -9223372036854775808 0Sample Output:Case #1: falseCase #2: trueCase #3: false
主要就是可能会溢出的问题，还有就是a+b只有赋值后才可以检测是否溢出。
溢出只可能发生在两正数相加或者两负数相加时，，所以把这两种溢出时的特殊情况拿出来单独考虑就可以了，其他情况是可以直接a+b的
#include <cstdio>int main(){int n,i;long long int a,b,c;scanf("%d",&n);for(i=1;i<=n;++i){bool flg = true;scanf("%lld %lld %lld",&a,&b,&c);long long res = a+b;if(a>0 && b>0 && res<=0)flg = true;else if(a<0 && b<0 && res>=0)flg = false;else{if(res<=c)flg = false;}if(flg){printf("Case #%d: true\n",i);}else{printf("Case #%d: false\n",i);}}return 0;}
近朱者赤，近墨者黑
