【c++程序】任意给两个日期，计算相差多少天和各自星期几

#include<iostream>using namespace std;struct Date{int y;//yearint m;//monthint d;//day in month};bool isLeap(int y)//判断是否是闰年{return y%4==0&&y%100!=0||y%400==0;//真返回为1，假为0}int daysOfMonth(int y,int m){int day[12]={31,28,31,30,31,30,31,31,30,31,30,31};if(m!=2)return day[m-1];else return 28+isLeap(y);}int daysOfDate(Date d)//计算一共的天数{int days=d.d;for(int y=1;y<d.y;y++)//计算年days+=365+isLeap(y);for(int m=1;m<d.m;m++)//计算月days+=daysOfMonth(d.y,m);//days+=d.d;return days;}int main(){Date d1,d2;cout<<"intput 2 dates(yyyy mm dd):";cin>>d1.y>>d1.m>>d1.d;cin>>d2.y>>d2.m>>d2.d;int days1=daysOfDate(d1);int days2=daysOfDate(d2);cout<<"difference:"<<days2-days1<<endl;cout<<"weekday"<<days1%7<<"\t"<<days2%7<<endl;return 0;}

，天再高又怎样，踮起脚尖就更接近阳光。