HDU 1076 An Easy Task

/*算闰年,思路简单,,按照题目的要求就行了判断闰年的条件((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)*/# include <stdio.h>int judge_leap(int year){if(((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))return 1;return 0;}int main(void){int T;scanf("%d", &T);getchar(); //吸收回车符。while(T–){ int year,N;scanf("%d %d", &year, &N);while(N){int temp = judge_leap(year);if(temp == 1)N–;if(N == 0) //当N=0时,此时已经算到了第N个闰年了,不能year++break;year++;}printf("%d\n", year);}return 0;}

人生的大部份时间里,承诺同义词是束缚,奈何我们向往束缚。

HDU 1076 An Easy Task

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