HDU2544 最短路 Dijkstra实现

题目

?pid=2544

代码;const int INF = 1000000000;const int max_v = 110;const int max_e = 10010;struct edge {int to,cost;};vector<edge> eg[max_v];int d[max_v];bool used[max_v];typedef pair<int,int> P;int e,v;int main(){while(scanf(“%d%d”,&v,&e) && v) {for(int i = 0 ; i < max_v ; i ++) {d[i] = INF;used[i] = false;}d[1] = 0;for(int i = 0 ; i < max_v ; i ++) eg[i].clear();for(int i = 1 ; i <= e ; i ++) {int a,b,c;scanf(“%d%d%d”,&a,&b,&c);edge d;d.to = b;d.cost = c;eg[a].push_back(d);d.to = a;eg[b].push_back(d);}//Dijkstrapriority_queue< P,vector<P>,greater<P> > que;que.push(P(0,1));while(!que.empty()) {P p = que.top();que.pop();int v = p.second;if(used[v]) continue;used[v] = true;for(int i = 0 ; i < eg[v].size() ; i ++) {edge ee = eg[v][i];if(d[ee.to] > d[v] + ee.cost) {d[ee.to] = d[v] + ee.cost;que.push(P(d[ee.to],ee.to));}}}printf(“%d\n”,d[v]);}return 0;}

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HDU2544 最短路 Dijkstra实现

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