题目：
Beat the Spread!Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5169Accepted Submission(s): 2692
Problem Description
Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.Given the winning numbers for each type of bet, can you deduce the final scores?
Input
The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.
Output
For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing "impossible". Recall that football scores are always non-negative integers.
Sample Input
240 2020 40
Sample Output
30 10impossible
Source
University of Waterloo Local Contest 2005.02.05
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题目分析：
已知a+b和a-b求a、b。
代码如下：
/* * b.cpp * * Created on: 2015年3月12日 *Author: Administrator */#include <iostream>#include <cstdio>using namespace std;int main(){int t;scanf("%d",&t);while(t–){int sum;int diff;scanf("%d%d",&sum,&diff);if(sum < diff){//如果两个数的和<两个数的差printf("impossible\n");//不可能有结果(a,b均>=0)}else if((sum+diff)%2 != 0){//如果(a+b) + (a-b) 不是偶数printf("impossible\n");//不可能}else{//否则符合正常逻辑printf("%d %d\n",(sum+diff)/2,(sum-diff)/2);//计算这两个数都是什么}}return 0;}
，可以以心感悟，以此沉淀，足矣;耳听佳音，目极美好，
