有个url如下:
?from=http%3a%2f%2fwrite.blog.csdn.net%2fpostedit
我们该如何获取from这个参数的值呢?在网上搜了下方法很简单,如下,,第一种是通过正则,第二种通过切串放进数组的方式:
方法一:
function getQueryString(name) {var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");var r = window.location.search.substr(1).match(reg);if (r != null) return unescape(r[2]); return null;}var from = getQueryString("from");alert(from);
方法二:
function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) {var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) {theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); } } return theRequest; } var req = GetRequest(); var from = req['from'];alert(from);
记忆的屏障,曾经心动的声音已渐渐远去。