二叉树递归,非递归实现(附代码)深度,叶子节点数量,逐行打印二

昨天晚上没有发文章,说来话长啊,昨天不知道是csdn的问题,还是我的问题,我访问了半天,访问不上网站啊,后来12点多了,就睡了。上一篇文章说到了二叉树的先序,中序,后序遍历问题,这次还是说的简单的一点,说计算二叉树的深度,和叶子节点数量

int ceng(Node *pRoot)//计算层数,递归实现{int left = 0;int right = 0;int res = 0;if (pRoot == NULL){return 0;}if (pRoot->pLeft != NULL){left = ceng(pRoot->pLeft);}if (pRoot->pRight != NULL){right = ceng(pRoot->pRight);}res = left > right ? left : right;return res + 1;}

class CengNode{public:int n = 0;Node *p = NULL;CengNode(int now, Node *p) :n(now), p(p){}};int cengstack(Node *pRoot)//计算深度,非递归实现{stack<CengNode> mystack;Node *pnow = pRoot;mystack.push(CengNode(1, pRoot));int res = 0;while (false == mystack.empty()){CengNode now = mystack.top();mystack.pop();if (now.n > res){res = now.n;}if (now.p->pRight != NULL){mystack.push(CengNode(now.n + 1, now.p->pRight));}if (now.p->pLeft != NULL){mystack.push(CengNode(now.n + 1, now.p->pLeft));}}return res;}

int getyenum(Node *pRoot)//计算叶子节点数,递归实现{int left = 0;int right = 0;if (pRoot == nullptr){return 0;}if (pRoot->pLeft == NULL && pRoot->pRight == NULL){return 1;}if (pRoot->pLeft != nullptr){left = getyenum(pRoot->pLeft);}if (pRoot->pRight != nullptr){right = getyenum(pRoot->pRight);}return left + right;}int getyenumstack(Node *pRoot)//计算叶子节点数,非递归实现{stack<Node *> mystack;Node *pnow = NULL;mystack.push(pRoot);int res = 0;while (false == mystack.empty()){pnow = mystack.top();mystack.pop();if (pnow != NULL){if (pnow->pLeft == NULL && pnow->pRight == NULL){res += 1;}else{if (pnow->pRight != NULL){mystack.push(pnow->pRight);}if (pnow->pLeft != NULL){mystack.push(pnow->pLeft);}}}}return res;}void hengprintqueue(Node *pRoot)//逐行打印,非递归,队列实现{queue<Node *> myqueue;myqueue.push(pRoot);Node *pnow = NULL;while (false == myqueue.empty()){pnow = myqueue.front();myqueue.pop();if (pnow != NULL){cout << pnow->data << " ";if (pnow->pLeft != NULL){myqueue.push(pnow->pLeft);}if (pnow->pRight != NULL){myqueue.push(pnow->pRight);}}}}void hengprintstack(Node *pRoot)//逐行打印,非递归,栈实现{stack<Node *> mystack;stack<Node *> mystacktemp;mystack.push(pRoot);Node *pnow = NULL;bool flag = true;while (false == mystacktemp.empty() || false == mystack.empty()) {if(false == mystack.empty()){pnow = mystack.top();mystack.pop();if (pnow != NULL){cout << pnow->data << " ";mystacktemp.push(pnow->pLeft);mystacktemp.push(pnow->pRight);}}else{while (false == mystacktemp.empty()){mystack.push(mystacktemp.top());mystacktemp.pop();}}}}自己感觉这些代码,还算是二叉树里面比较简单的吧,具体的就不解释了,相信大家还是都能理解的,递归的好理解,栈就是我们手动模拟递归的过程啊。

说说这几天的感受,说好的15号结束c++啊,今天都17号了,其实这个东西不能急功近利啊,真的是只能慢慢来,从上个月18号开始的c++吧,不知不觉过了1个月了,其实现在感觉c++的语言还好吧,主要是基本功,数据结构,还有设计模式,因为以前用别的语言做过打的项目,所以其实设计模式还好,主要就是数据结构,树和图,还有n种排序算法,所以这几天真的发现越学东西越多啊,总之,这个坎是要迈过去的,我要在6月之前尽力搞啊,时间也算是够长的,具体的看自己了。

基础不牢地动山摇,如果想要好的offer,好的工作就要努力啊,加油吧。明天还要调整一下学习计划,,复习一下,我们一起搞,搞cocos2dx,搞数据结构,搞设计模式,

我去刷牙了,一会儿就睡觉了。

觉得自己做的到和不做的到,其实只在一念之间

二叉树递归,非递归实现(附代码)深度,叶子节点数量,逐行打印二

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