寻找星空の孩子的专栏

Romantic

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3218 Accepted Submission(s): 1274

Problem Description The Sky is Sprite. The Birds is Fly in the Sky. The Wind is Wonderful. Blew Throw the Trees Trees are Shaking, Leaves are Falling. Lovers Walk passing, and so are You. …………………………..Write in English class by yifenfei

Girls are clever and bright. In HDU every girl like math. Every girl like to solve math problem! Now tell you two nonnegative integer a and b. Find the nonnegative integer X and integer Y to satisfy X*a + Y*b = 1. If no such answer print “sorry” instead.

Input The input contains multiple test cases. Each case two nonnegative integer a,b (0< a, b<=2^31)

Output output nonnegative integer X and integer Y, if there are more answers than the X smaller one will be choosed. If no answer put “sorry” instead.

Sample Input 77 51 10 44 34 79

Sample Output 2 -3 sorry 7 -3

Author yifenfei

题意很简单就是a * x + b * y = 1注意的是X必须大于0 SO… a*(x+b) + b*(y-a) = a*x + a*b + b*y – a*b = 1

#include<stdio.h>#define LL __int64void exgcd(LL a,LL b,LL& d,LL& x,LL& y){if(!b)d=a,x=1,y=0;else{exgcd(b,a%b,d,y,x);y-=x*(a/b);}}int main(){LL a,b;while(scanf(“%I64d%I64d”,&a,&b)!=EOF){LL d,x,y;exgcd(a,b,d,x,y);if(d==1){while(x<0){//a * x + b * y = 1//-> a-a) = a*x + a*b + b*y – a*b = 1x = x+b;y = y-a;}printf(“%I64d %I64d\n”,x,y);}elseprintf(“sorry\n”);}return 0;}

,都在努力为你驱逐烦恼焦躁,

寻找星空の孩子的专栏

相关文章:

你感兴趣的文章:

标签云: