上一篇大概的讲了下实现吸入吸出Mesh效果的简单例子，经过进一步研究，发现和百度阅读的仍有一定差距。
下面是最新研究的效果：
发现关键点在于滑动的同时，不只是Mesh的点发生变化。轨迹线也在变，所以在改变drawBitmapMesh 中的点时，需要改变线的轨迹。
增加一个改变线的函数：
<span style="font-size:24px;">public void buildPaths(int timeIndex){float w = mBmpWidth;float h = mBmpHeight;mTimeIndex = timeIndex;mFirstPathMeasure.setPath(mFirstPath, false);mSecondPathMeasure.setPath(mSecondPath, false);float[] pos1 = {0.0f, 0.0f};float[] pos2 = {0.0f, 0.0f};float firstLen = mFirstPathMeasure.getLength();float secondLen = mSecondPathMeasure.getLength();float len1 = firstLen / mHorizontalSplit;float len2 = secondLen / mHorizontalSplit;float firstPointDist = timeIndex * len1;float secondPointDist = timeIndex * len2;mFirstPathMeasure.getPosTan(firstPointDist, pos1, null);mSecondPathMeasure.getPosTan(secondPointDist, pos2, null);w = mPathendX;Log.i("yunli", "timeIndex = " + timeIndex +", w = " + w);if(timeIndex < 4*mHorizontalSplit/10){mThirdPath.reset();mForthPath.reset();mThirdPath.moveTo(pos1[0], h/2);mForthPath.moveTo(pos2[0], h/2);mThirdPath.cubicTo(pos1[0], pos1[1],w/8+pos1[0],10,3*w/8,10);mForthPath.cubicTo(pos2[0], pos2[1],w/8+pos2[0],h-10, 3*w/8, h-10);mThirdPath.quadTo((5*w ) / 8, 15, w, h/2-4);mForthPath.quadTo((5*w ) / 8,h-15, w, h/2+4);}else if(timeIndex == 4*mHorizontalSplit/10){mThirdPath.reset();mForthPath.reset();mThirdPath.moveTo(pos1[0], h/2);mForthPath.moveTo(pos2[0], h/2);mThirdPath.cubicTo(pos1[0], pos1[1],5*w/8,15,w,h/2-4);mForthPath.cubicTo(pos2[0], pos2[1],5*w/8,h-15, w, h/2+4);}else{mThirdPath.reset();mForthPath.reset();mThirdPath.moveTo(pos1[0], h/2);mForthPath.moveTo(pos2[0], h/2);mThirdPath.quadTo(pos1[0], pos1[1], w, h/2-4);mForthPath.quadTo(pos2[0], pos2[1], w, h/2+4);}}</span>思路是，先画出最原始的轨迹线，随着timeindex的变化，画出不同的线，而只有在画Mesh点的时候，
才将PathMeasure上放置第3和4条临时线，，算临时线位置的时候永远取第一和第二条。上面的方法在上一篇文章中都有介绍，
主要是画贝塞尔曲线。下载链接：
点击打开链接
所以你不懂我的选择，也可以不懂我的难过，
