You are climbing a stair case. It takesnsteps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
题意: 求上n个台阶的方法数,要么走一步,,要么两步。
思路:递归超时,递推
class Solution {public:int climbStairs(int n) {if (n <= 2) return n;int f[1000];f[1] = 1, f[2] = 2;for (int i = 3; i <= n; i++)f[i] = f[i-1] + f[i-2];return f[n];}};
别人失去了信心,他却下决心实现自己的目标。