#!/usr/bin/pythonfrom time import clockl = [(x,x) for x in xrange (10000000)] d = dict(l) t0 = clock() # 方法一for i in d:n = d[i]t1 = clock() # 方法二：最慢for k,v in d.items():n = vt2 = clock() # 方法三: 最快，推荐方法for k,v in d.iteritems():n = v t3 = clock() # 方法四for k,v in zip(d.iterkeys(),d.itervalues()):n = v t4 = clock() print t1 – t0, t2 – t1, t3 – t2, t4 – t3
以上代码执行五次，结果分别为：
rootrootrootrootroot
可见，，最快的方法是：
for k,v in d.iteritems():…
通电话，旅行，重复一个承诺和梦想，
