leetcode 201: Bitwise AND of Numbers Range

Bitwise AND of Numbers Range

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

[思路]

等价于 求 m 与 n 二进制编码中 同为1的前缀.

[CODE]

public class Solution {public int rangeBitwiseAnd(int m, int n) {int bit = 0;while(m!=n) {m>>=1;n>>=1;bit++;}return m<<bit;}}

，都懒得写日记来记录，可见内心底对旅行是多么的淡漠。