Valid NumberValidate if a given string is numeric.Some examples:"0" => true" 0.1 " => true"abc" => false"1 a" => false"2e10" => trueNote: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.Update (2015-02-10):
The signature of the C++ function had been updated. If you still see your function signature accepts a const char * argument, please click the reload button to reset your code definition.
思路：此题是真的有些难度的，而且最重要的是我根本就不清楚一个有效数字的规则。。。一个连规则都不知道的人怎么能玩好游戏呢，，所以果断的挂了10次8次的，最后还是没有完全答对。暂时把别人的代码拿出来放在下面，有时间再好好研究一下：
public class Solution {public boolean isNumber(String s) {// Start typing your Java solution below// DO NOT write main() function/*"0" => true"0.1" => true"abc" => false"1 a" => false"+-2e10" => true//*///check input.if(s==null || s.length()==0) return false;int sz = s.length();int i=0;while(i<sz && s.charAt(i)==' ') ++i;boolean space = false;boolean exp = false;boolean dot = false;boolean number = false;boolean neg = false;for(; i<sz; i++) {char c = s.charAt(i);if(c==' ') {space = true;} else if(space==true) {return false;} else if( (c=='e' || c=='E') && exp==false && number==true) {exp = true;number = false;dot = true;neg = false;} else if( c=='.' && dot==false) {dot = true;neg = true;// number = false;} else if( c>='0' && c<='9') {number = true;} else if((c=='+' || c=='-') && neg==false && number==false ) {neg = true;} else {return false;}}return number;}}
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眼睛可以近视，目光不能短浅。
