Unique Paths II(唯一路径问题II)】

【LeetCode-面试算法经典-Java实现】【063-Unique Paths II(唯一路径问题II)】

分类:LeetCode

【063-Unique Paths II(唯一路径问题II)】【LeetCode-面试算法经典-Java实现】【所有题目目录索引】原题

  Follow up for “Unique Paths”:   Now consider if some obstacles are added to the grids. How many unique paths would there be?   An obstacle and empty space is marked as 1 and 0 respectively in the grid.   For example,   There is one obstacle in the middle of a 3×3 grid as illustrated below.

[ [0,0,0], [0,1,0], [0,0,0]]

  The total number of unique paths is 2.   Note: m and n will be at most 100.

题目大意

  唯一路径问题后续,如果路径中有障碍,求总的路径的种数。【唯一路径问题】   注意:网格的行数和列数都不超过100

解题思路

  采用分治求解方法   用一个m*n的组数A保存结果。   对于A数组中的元素有。   1、当x=0或者y=0时,并且(x, y)位置无障碍。有A[x][y] = 1; 有障碍就是0   2、当x>=1并且y>=1时,并且(x, y)位置无障碍。有A[x][y] = A[x-1][y]+A[x][y-1]。 有障碍就是0   3、所求的结点就是A[m-1][n-1]。

代码实现

算法实现类

public class Solution {(int[][] obstacleGrid) {// 输入校验if (obstacleGrid == null || obstacleGrid.length < 1 || obstacleGrid[0].length < 1|| obstacleGrid[0][0] == 1|| obstacleGrid[obstacleGrid.length – 1][obstacleGrid[0].length – 1] == 1) {return 0;}int rows = obstacleGrid.length;int cols = obstacleGrid[0].length;int[][] result = new int[rows][cols];// 第一个位置有多少种方法,无障碍就是1种,有障碍就是0种result[0][0] = obstacleGrid[0][0] == 0 ? 1 : 0;for (int i = 1; i < cols; i++) {result[0][i] = obstacleGrid[0][i] == 0 ? result[0][i – 1] : 0;}for (int i = 1; i < rows; i++) {result[i][0] = obstacleGrid[i][0] == 0 ? result[i – 1][0] : 0;}for (int i = 1; i < rows; i++) {for (int j = 1; j < cols; j++) {result[i][j] = obstacleGrid[i][j] == 0 ? result[i – 1][j] + result[i][j – 1] : 0;}}return result[rows – 1][cols – 1];}(int[][] obstacleGrid) {// 输入校验if (obstacleGrid == null || obstacleGrid.length < 1 || obstacleGrid[0].length < 1|| obstacleGrid[obstacleGrid.length – 1][obstacleGrid[0].length – 1] == 1) {return 0;}int[] result = {0};solve(obstacleGrid, 0, 0, result);return result[0];}(int[][] grid, int row, int col, int[] sum) {// 到达终点if (row == grid.length – 1 && col == grid[0].length – 1) {sum[0]++;}(row >= 0 && row < grid.length && col >= 0 && col < grid[0].length && grid[row][col] == 0) {// 往右走solve(grid, row, col + 1, sum);// 往下走solve(grid, row + 1, col, sum);}}}评测结果

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Unique Paths II(唯一路径问题II)】

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