Problem Description
The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very… easy problem.Give you an operator (+,-,*, / –denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.Is it very easy? Come on, guy! PLMM will send you a beautiful Balloon right now!Good Luck!
Input
Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator.
Output
For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.
Sample Input
4+ 1 2- 1 2* 1 2/ 1 2
Sample Output
3-120.50
这里需要注意的是小数点的取舍 System.out.printf("%.2f",(float)x/y);
package HDU;import java.util.Scanner;public class P1170 {public static void main(String[] args) {Scanner sc=new Scanner(System.in);int n=sc.nextInt();while(n–>0){String a=sc.next();char b=a.charAt(0);int x= sc.nextInt();int y=sc.nextInt();int sum=0;if(b=='+'){sum=x+y;System.out.println(sum);}if(b=='-'){sum=x-y;System.out.println(sum);}if(b=='*'){sum=x*y;System.out.println(sum);}if(b=='/'){if(x%y==0){System.out.println(x/y);}//这里注意，看清题目意思else{System.out.printf("%.2f",(float)x/y);System.out.println();}}}}}
，孤独是为了孤独背后的解脱，孤独的过程，就是一个寻找真爱的过程。
