Find all possible combinations of k numbers that add up to a numbern, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Ensure that numbers within the set are sorted in ascending order.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
Solution:
DFS, two conditions for basic case, one is sum , second is k number
public List<List<Integer>> combinationSum3(int k, int n) {List<List<Integer>> result = new ArrayList<>();List<Integer> cur = new ArrayList<>();if(k<1 || n<1 || k>n) return result;dfs(result, cur, 0, k, n, 1);return result;}public void dfs(List<List<Integer>> result, List<Integer> cur, int sum, int k, int n, int level) {if(sum == n && k==0) {result.add(new ArrayList(cur));return;} else if(sum> n || k<0) return;for(int i=level;i<=9;i++){cur.add(i);dfs(result, cur, sum+i, k-1, n, i+1);cur.remove(cur.size()-1);}}
版权声明:本文为博主原创文章,,未经博主允许不得转载。
躲在某一地点,想念一个站在来路,