args就是所有参数的数组,kwargs就是当你传入key=value是存储的字典,当函数的参数不确定时,可以使用*args 和kwargs,*args 没有key值,kwargs有key值
def fun_var_args(farg, *args): print "arg:", farg for value in args: print "another arg:", value fun_var_args(1, "two", 3) # *args可以当作可容纳多个变量组成的list
result:
arg: 1 another arg: two another arg: 3
**kwargs:
def fun_var_kwargs(farg, **kwargs): print "arg:", farg for key in kwargs: print "another keyword arg: %s: %s" % (key, kwargs[key]) fun_var_kwargs(farg=1, myarg2="two", myarg3=3) # myarg2和myarg3被视为key, 感觉**kwargs可以当作容纳多个key和value的dictionary
result:
arg: 1 another keyword arg: myarg2: two another keyword arg: myarg3: 3
也可以用下面的形式:
def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 args = ["two", 3] #list fun_var_args_call(1, *args)
result:
arg1: 1 arg2: two arg3: 3
def fun_var_args_call(arg1, arg2, arg3): print "arg1:", arg1 print "arg2:", arg2 print "arg3:", arg3 kwargs = {"arg3": 3, "arg2": "two"} # dictionary fun_var_args_call(1, **kwargs)
result:
arg1: 1 arg2:"two" arg3:3
当所有传参为key=value形式将返回字典形式
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Copyright ??颓废的腰子技术Blog [Python中的*args 和**kwargs的用法], All Right Reserved. 2015. 人,总是很难改正自己的缺点,
Copyright ??颓废的腰子技术Blog [Python中的*args 和**kwargs的用法], All Right Reserved. 2015. 人,总是很难改正自己的缺点,