解决py2exe生成windows服务不能正常启动的问题

使用py2exe生成windows服务在win7下可以正常运行，但是到了xp下面可以安装，但是无法启动；报“服务没有及时响应或控制请求”的错误，改用pyinstaller生成也是不行；查资料后修改setup.py如下即可,服务名、脚本名请自行替换：

#!/usr/bin/python  #-*-coding:cp936-*-from distutils.core import setupimport py2execlass Target:    def __init__(self, **kw):        self.__dict__.update(kw)        # for the versioninfo resources        self.version = "1.1.8"        self.company_name = "Yovole Shanghai Co. Ltd."        self.copyright = "Copyright (c) 2013 Founder Software (Shanghai) Co., Ltd. "        self.name = "Guest Agent"myservice = Target(    description = 'Yovole Cloud Desktop Guest Agent',    modules = ['service'],    cmdline_style='pywin32'    #icon_resources=[(1, "cartrigde.ico")] )options = {"py2exe":               {   "compressed": 1,                   "bundle_files": 1             }             }  setup(    service=[myservice],    options = options,     zipfile = None,    windows=[{"script": "service.py"}], )