删除原字符串中所有匹配的子串，并返回匹配的子串个数
1、删除子串，只要是原串中有相同的子串就删掉，不管有多少个，返回子串个数。
#include <stdio.h>#include <stdlib.h>#include <assert.h>#include <string.h>int delete_sub_str(const char *str,const char *sub_str,char *result){assert(str != NULL && sub_str != NULL);const char *p,*q;char *t,*temp;p = str;q = sub_str;t = result;int n,count = 0;n = strlen(q);temp = (char *)malloc(n+1);memset(temp,0x00,n+1);while(*p){memcpy(temp,p,n);if(strcmp(temp,q) == 0 ){count++;memset(temp,0x00,n+1);p = p + n;}else{*t = *p;p++;t++;memset(temp,0x00,n+1);}}free(temp);return count;}void main(){char s[100] = {‘\0’}; int num = delete_sub_str(“123abc12de234fg1hi34j123k”,”123″,s);printf(“The number of sub_str is %d\r\n”,num);printf(“The result string is %s\r\n”,s);getchar();}
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，木已成舟便要顺其自然
