C语言实现扫雷小游戏简单版

本文实例为大家分享了C语言实现扫雷小游戏的具体代码,供大家参考,具体内容如下

在vs2019创建新项目,然后添加两个源文件test.c和game.c,接着创建一个头文件game.h。

test.c:

#include "game.h" void game(){ char mine[ROWS][COLS] = { 0 }; char show[ROWS][COLS] = { 0 };  InitBoard(mine, ROWS, COLS, '0'); InitBoard(show, ROWS, COLS, '*');  SetMine(mine, ROW, COL);  //DispalyBoard(mine, ROW, COL); DispalyBoard(show, ROW, COL);  FindMine(mine, show, ROW, COL);} void menu(){ printf("**************************\n"); printf("******    1.play    ******\n"); printf("******    0.exit    ******\n"); printf("**************************\n");} int main(){ int input = 0; srand((unsigned int)time(NULL)); do {  menu();  printf("请输入:");  scanf("%d", &input);  switch (input)  {  case 1:   game();   break;  case 0:   printf("退出游戏\n");   break;  default:   printf("输入错误,请重新输入\n");   break;  } } while (input); return 0;}

game.c:

#include "game.h" void InitBoard(char board[ROWS][COLS], int rows, int cols, char set){ int i = 0; for (i = 0; i < rows; i++) {  int j = 0;  for (j = 0; j < cols; j++)  {   board[i][j] = set;  } }}  void DispalyBoard(char board[ROWS][COLS], int row, int col){ int i = 0; for (i = 0; i <= 9; i++) {  printf("%d ", i); } printf("\n"); for (i = 1; i <= row; i++) {  int j = 0;  printf("%d ", i);  for (j = 1; j <= col; j++)  {   printf("%c ", board[i][j]);  }  printf("\n"); }}  void SetMine(char board[ROW][COL], int row, int col){ int count = EASY_COUNT; while (count) {  int x = rand() % row + 1;  int y = rand() % col + 1;  if (board[x][y] != '1')  {   board[x][y] = '1';   count--;  } }}  int GetMineCount(char mine[ROWS][COLS], int x, int y){ return (mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y - 1] +  mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1] - 8 * '0');} void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){ int x = 0; int y = 0; int win = 0; while (win<row*col-EASY_COUNT) {  printf("请输入要排查的坐标:");  scanf("%d%d", &x, &y);   if (x >= 1 && x <= row && y >= 1 && y <= col)  {   if (mine[x][y] == '1')   {    printf("很遗憾,你被炸死了\n");    DispalyBoard(mine, ROW, COL);    break;   }   else   {    int count = GetMineCount(mine, x, y);    show[x][y] = count + '0';    DispalyBoard(show, ROW, COL);    win++;   }  }  else  {   printf("坐标非法,请重新输入\n");  } } if (win == row * col - EASY_COUNT) {  printf("排雷成功\n"); }}

game.h:

#pragma once #include <stdio.h>#include <stdlib.h>#include <time.h> #define ROW 9#define COL 9 #define EASY_COUNT 10#define ROWS ROW+2#define COLS COL+2void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);void DispalyBoard(char board[ROWS][COLS], int row, int col);void SetMine(char board[ROWS][COLS], int row, int col);void FindMine(char mine[ROW][COL], char show[ROW][COL], int row, int col);

运行效果如图:

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

积极的人在每一次忧患中都看到一个机会,

C语言实现扫雷小游戏简单版

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