C语言实现三子棋(井字棋)算法

本文实例为大家分享了C语言实现三子棋算法,供大家参考,具体内容如下

游戏文件主干(test.c):

#include"game.h" void menu()//游戏菜单{ printf("************************************************\n"); printf("**********          1.play             *********\n"); printf("**********          0.exit             *********\n"); printf("************************************************\n");}void game()//游戏玩法实现主体(粗略){ printf("三子棋:>\n"); char board[LINE][ROW]; Init_checkerboard(board, LINE, ROW);//初始化棋盘 Print_checkerboard(board, LINE, ROW);//打印棋盘 char ret = 0; while (1)//条件为1可以一直循环 {  Player_game(board, LINE, ROW);//玩家行动  Print_checkerboard(board, LINE, ROW);//玩家行动后的棋盘  ret = Iswin(board, LINE, ROW);//判断是否出现胜负  if (ret != 'c')//出现胜负就跳出循环  {   break;  }  Commputer_game(board, LINE, ROW);//电脑回合  Print_checkerboard(board, LINE, ROW);//电脑行动后的棋盘  ret = Iswin(board, LINE, ROW);//判断是否出现胜负  if (ret != 'c')  {   break;  }   }  if (ret == '*')  {   printf("玩家胜利!\n");  }  else if (ret == '#')  {   printf("电脑胜利!\n");  }  else  {   printf("平局\n");  }  } int main()//整个源文件的入口{ int input = 0; srand((unsigned int)time(NULL));//电脑下棋的随机数 do {  menu();  printf("请选择:>");  scanf("%d", &input);  switch (input)  {  case 1:   game();//游戏函数主题(粗略)   break;  case 0:   printf("您已退出游戏!\n");   break;  default:   printf("输入数字无效,请重新输入");   break;  } } while (input); return 0;}

游戏主干(game.c):

#include"game.h"//游戏主干(详细)void Init_checkerboard(char board[LINE] [ROW], int line, int row){ int i = 0; int j = 0; for ( i = 0; i <line; i++) {  for ( j = 0; j <row; j++)  {   board[i][j]=' ';  } }}//棋盘的初始化 void Print_checkerboard(char board[LINE][ROW], int line, int row){ int i = 0; for (i = 0; i < line; i++) {  int j = 0;  for (j = 0; j < line; j++)  {   printf(" %c ",board[i][j]);   if (j < row - 1)   {    printf("|");   }  }  printf("\n");  if (i < row - 1)  {   for (j = 0; j < row; j++)      {    printf("---");    if (j < row - 1)    {     printf("|");    }   }  }  printf("\n"); }}//生成3-3的棋盘 void Player_game(char board[LINE][ROW], int line, int row){ printf("玩家下棋:>"); int x = 0; int y = 0; while (1) {  printf("请输入想要下棋的位置坐标:>");  scanf("%d%d",&x,&y);  if (x >= 1 && x <= line && y >= 1 && y <= row)  {   if (board[x - 1][y - 1] == ' ')   {    board[x - 1][y - 1] = '*';    break;   }   else   {    printf("坐标被占用,请重新输入\n");   }  }  else  {   printf("非法坐标,超出范围\n");  } }}//玩家行动的限制与实现  void Commputer_game(char board[LINE][ROW], int line, int row){ int x = 0; int y = 0; while (1) {  x = rand() % line;  y = rand() % row;  if (board[x][y]==' ')  {   board[x][y] = '#';   break;  } }}//电脑行动的限制与实现  char con(char board[LINE][ROW], int line, int row){ int i = 0; int j = 0; for (i = 0; i < line; i++) {  for (j = 0; j < row; j++)  {   if (board[i][j] == ' ')   {    return 'a';   }  } }}//判断游戏是否继续的实现 char rank(char board[LINE][ROW], int line, int row){ int i = 0; int j = 0; for (i = 0; i < row; i++) {  for (j = 0; j < line; j++)  {   if (board[j][i] == '*' && board[j][i] == board[j+1][i] && board[j+2][i] == board[j][i])   {    return 'q';   }   else if (board[j][i] == '#' && board[j][i] == board[j + 1][i] && board[j + 2][i] == board[j][i])   {    return 'w';   }  } }}//判断一列的胜负条件 char Iswin(char board[LINE][ROW], int line, int row)//判断胜负的条件{ int i = 0; int j = 0; for (i = 0; i < line; i++) {  for (j = 0; j < row; j++)  {    //判断行的胜负条件   if (board[i][j] == board[i][j + 1] && board[i][j] == '*' && board[i][j] == board[i][j + 2])   {     return '*';   }   else if (board[i][j] == '#' && board[i][j] == board[i][j + 1] && board[i][j] == board[i][j + 2])   {    return '#';   }   //判断列   else if (rank(board,LINE,ROW)=='q')   {     return '*';   }   else if (rank(board, LINE, ROW) == 'w')   {     return '#';   }   //对角线判断   else if ((board[i][j] == board[i + 1][j + 1] && board[i][j] == board[i + 2][j + 2] && board[i][j] == '*') || (board[i][j + 2] == board[i + 1][j + 1] && board[i + 2][j] == board[i][j + 2] && board[i][j + 2] == '*'))   {     return '*';   }   else if ((board[i][j] == board[i + 1][j + 1] && board[i][j] == board[i + 2][j + 2] && board[i][j] == '#') || (board[i][j + 2] == board[i + 1][j + 1] && board[i + 2][j] == board[i][j + 2] && board[i][j + 2] == '#'))   {     return '#';   }   else if (con(board, LINE, ROW) == 'a')   {    return 'c';   }   else   {    return 'p';   }  } } return 0;}

游戏的头文件(game.h):

#pragma once//保证被重复调用后依然只执行一次#include<stdio.h>#include<stdlib.h>#include<time.h> #define LINE 3#define ROW  3 //初始化棋盘:extern void Init_checkerboard(char board[LINE][ROW], int line, int row);//打印棋盘:extern void Print_checkerboard(char board[LINE][ROW], int line, int row);//玩家走:extern void Player_game(char board[LINE][ROW], int line, int row);//电脑走:extern void Commputer_game(char board[LINE][ROW], int line, int row);//判断胜负:extern char Iswin(char board[LINE][ROW], int line, int row);

代码运行图:

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

就看你能不能战胜它。战胜了,你就是英雄,就是生活的强者。

C语言实现三子棋(井字棋)算法

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