[LeetCode] 38. Count and Say 计数和读法
The count-and-say sequence is the sequence of integers with the first five terms as following:
1. 12. 113. 214. 12115. 111221
1 is read off as ”one 1″ or 11.11 is read off as ”two 1s” or 21.21 is read off as ”one 2, then one 1″ or 1211.
Given an integer n where 1 ≤ n ≤ 30, generate the nth term of the count-and-say sequence.
Note: Each term of the sequence of integers will be represented as a string.
Example 1:
Input: 1Output: “1”
Example 2:
Input: 4Output: “1211”
这道计数和读法问题还是第一次遇到,看似挺复杂,其实仔细一看,算法很简单,就是对于前一个数,找出相同元素的个数,把个数和该元素存到新的 string 里。代码如下:
class Solution {public: string countAndSay(int n) { if (n <= 0) return ""; string res = "1"; while (--n) { string cur = ""; for (int i = 0; i < res.size(); ++i) { int cnt = 1; while (i + 1 < res.size() && res[i] == res[i + 1]) { ++cnt; ++i; } cur += to_string(cnt) + res[i]; } res = cur; } return res; }};
打印出了前 12 个数字,发现一个很有意思的现象,不管打印到后面多少位,出现的数字只是由 1, 2 和3 组成,前十二个数字如下:
11 12 11 2 1 11 1 1 2 2 13 1 2 2 1 11 3 1 1 2 2 2 11 1 1 3 2 1 3 2 1 13 1 1 3 1 2 1 1 1 3 1 2 2 11 3 2 1 1 3 1 1 1 2 3 1 1 3 1 1 2 2 1 11 1 1 3 1 2 2 1 1 3 3 1 1 2 1 3 2 1 1 3 2 1 2 2 2 13 1 1 3 1 1 2 2 2 1 2 3 2 1 1 2 1 1 1 3 1 2 2 1 1 3 1 2 1 1 3 2 1 1
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