本文实例为大家分享了C/C++实现推箱子小游戏的具体代码，供大家参考，具体内容如下
效果演示
实现功能
如上图所示。按键控制小猪的运动，推箱子到达目的地。
如何实现
1.首先思考要保存箱子，小猪等信息，添加多个map可以用到三维数组。2.定义小猪，箱子，墙，空地等信息在三维数组里的数值。
空地 0 墙 1目的地 2 箱子 3猪 4 2+4=6 猪到达目的地也显示猪箱子到达目的地 2+3=5
3.按键实现推箱子运动。
考虑多种情况：
①.小猪的运动(空地，目的在)②.小猪推箱子运动(空地，目的地)
用三维数组保存map信息：这里我只做了两种图，可自行添加
int backgrand[MAP][ROW][COL] =//map图{ { 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 2, 0, 0, 1, 1, 1, 0, 0, 3, 1, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 3, 3, 2, 1, 1, 1, 0, 3, 2, 0, 0, 1, 1, 0, 0, 2, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 }, { 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 2, 0, 0, 0, 1, 1, 1, 0, 0, 3, 0, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 3, 2, 3, 0, 1, 1, 0, 0, 0, 0, 2, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1 },};
绘图用到了easyx库，加载图片和绘制窗口只用到了三条语句：很简单
initgraph();//绘制窗口大小loadimage();//加载图片putinmage();//放出图片
具体可看代码！
代码块
#include<stdio.h>#include<Windows.h>#include<stdlib.h>#include<time.h>#include<conio.h>#include<graphics.h>#define ROW 8#define COL 8#define MAP 2//map个可以自己添加数int count = 0;//哪个map图/*空地 0墙 1目的地 2箱子 3猪 4 2+4=6 猪到达目的地也显示猪箱子到达目的地 2+3=5*/IMAGE image1, image2, image3, image4, image5, image6;int backgrand[MAP][ROW][COL] =//map图{ { 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 2, 0, 0, 1, 1, 1, 0, 0, 3, 1, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 3, 3, 2, 1, 1, 1, 0, 3, 2, 0, 0, 1, 1, 0, 0, 2, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 }, { 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 2, 0, 0, 0, 1, 1, 1, 0, 0, 3, 0, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 3, 2, 3, 0, 1, 1, 0, 0, 0, 0, 2, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1 },};int Judge(){//p判断是否结束一局 int i = 0; for (i = 0; i < ROW; i++){ int j = 0; for (j = 0; j < COL; j++){ if (backgrand[count][i][j] == 3 || backgrand[count][i][j] == 2){//判断是否还有箱子或者目的地 return 0; } } } return 1;}void Backgrand(){//绘制地图 int i = 0; for (; i < ROW; i++){ int j = 0; for (; j < COL; j++){ int x = 80 * j;//横轴是y(列)，数轴是x（行）。 int y = 80 * i; switch (backgrand[count][i][j]){ case 0: putimage(x, y, &image3); break; case 1: putimage(x, y, &image1); break; case 2: putimage(x, y, &image6); break; case 3: putimage(x, y, &image4); break; case 4: case 6: putimage(x, y, &image2); break; case 5: putimage(x, y, &image5); break; default: break; } } }}void Keymove(){//按键控制猪的运动 int i = 0; int j = 0;//j定义出来了，里面for循环要初始化 for (i = 0; i < ROW; i++){ //找到猪的坐标 for (j = 0; j < COL; j++){ if (backgrand[count][i][j] == 4 || backgrand[count][i][j] == 6){ break; } } if (backgrand[count][i][j] == 4 || backgrand[count][i][j] == 6){ break; } } char key = _getch();//获得按键 switch (key){ case 'w': case 'W': case 72: if (backgrand[count][i - 1][j] == 0 ||\ backgrand[count][i - 1][j] == 2) { backgrand[count][i][j] = backgrand[count][i][j] - 4;//猪运动，猪旁边是空地或者是目的地 backgrand[count][i - 1][j] = backgrand[count][i - 1][j] + 4; } if (backgrand[count][i - 1][j] == 3 && (backgrand[count][i - 2][j] == 0 || \ backgrand[count][i - 2][j] == 2)) //猪推箱子运动条件，猪旁边是箱子与上箱子旁边是空地。 { //后面或的条件要括号括起来 backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i - 1][j] = backgrand[count][i - 1][j] + 4; backgrand[count][i - 1][j] -= 3; backgrand[count][i - 2][j] += 3; } if (backgrand[count][i - 1][j] == 5 &&\ backgrand[count][i - 2][j] == 0) //箱子到达目的地，后面还有空的情况 { backgrand[count][i][j] -= 4; backgrand[count][i - 1][j] += 4; backgrand[count][i - 1][j] -= 3; backgrand[count][i - 2][j] += 3; } break; case 's': case 'S': case 80: if (backgrand[count][i + 1][j] == 0 || \ backgrand[count][i + 1][j] == 2) { //猪运动 backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i + 1][j] = backgrand[count][i + 1][j] + 4; } if (backgrand[count][i + 1][j] == 3 && (backgrand[count][i + 2][j] == 0 ||\ backgrand[count][i + 2][j] == 2)) { backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i + 1][j] = backgrand[count][i + 1][j] + 4; backgrand[count][i + 1][j] -= 3; backgrand[count][i + 2][j] += 3; } if (backgrand[count][i + 1][j] == 5 && \ backgrand[count][i + 2][j] == 0) { backgrand[count][i][j] -= 4; backgrand[count][i + 1][j] += 4; backgrand[count][i + 1][j] -= 3; backgrand[count][i + 2][j] += 3; } break; case 'a': case 'A': case 75: if (backgrand[count][i][j - 1] == 0 || \ backgrand[count][i][j - 1] == 2) { //猪运动 backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i][j - 1] = backgrand[count][i][j - 1] + 4; } if (backgrand[count][i][j - 1] == 3 &&\ (backgrand[count][i][j - 2] == 0 ||\ backgrand[count][i][j - 2] == 2)) { backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i][j - 1] = backgrand[count][i][j - 1] + 4; backgrand[count][i][j - 1] -= 3; backgrand[count][i][j - 2] += 3; } if (backgrand[count][i][j - 1] == 5 && \ backgrand[count][i][j - 2] == 0) { backgrand[count][i][j] -= 4; backgrand[count][i][j - 1] += 4; backgrand[count][i][j - 1] -= 3; backgrand[count][i][j - 2] += 3; } break; case 'd': case 'D': case 77: if (backgrand[count][i][j + 1] == 0 || \ backgrand[count][i][j + 1] == 2) { //猪运动 backgrand[count][i][j] = backgrand[count][i][j] - 4; backgrand[count][i][j + 1] = backgrand[count][i][j + 1] + 4; } if (backgrand[count][i][j + 1] == 3 && (backgrand[count][i][j + 2] == 0 ||\ backgrand[count][i][j + 2] == 2)) { backgrand[count][i][j] -= 4; backgrand[count][i][j + 1] += 4; backgrand[count][i][j + 1] -= 3; backgrand[count][i][j + 2] += 3; } if (backgrand[count][i][j + 1] == 5 && backgrand[count][i][j + 2] == 0){ backgrand[count][i][j] -= 4; backgrand[count][i][j + 1] += 4; backgrand[count][i][j + 1] -= 3; backgrand[count][i][j + 2] += 3; } break; default: break; }}void Initgraph(){ initgraph(80 * ROW, 80 * COL); loadimage(&image1, "1.jpg");//墙 loadimage(&image2, "2.jpg");//猪 loadimage(&image3, "3.jpg");//空地 loadimage(&image4, "4.jpg");//箱子 loadimage(&image6, "6.jpg");//目的地 loadimage(&image5, "5.jpg");//箱子到目的地}int main(){ Initgraph(); while (1){ Backgrand(); Keymove(); if (Judge()){ Backgrand(); Sleep(500); count++; } if (count == MAP){ break; } } getchar(); closegraph(); system("pause"); return 0;}
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。
命运如同手中的掌纹，无论多曲折，终掌握在自己手中。
