Linux下64位整数的使用有关问题

Linux下64位整数的使用问题
想在Linux(ubuntu kernel 2.6.21)下使用64位整数，有如下程序片断：

…
long long llNum = 0x1111222233334444; //(1)
…
printf("0x%x\n", llNum); //(2)
…

编译时提示(1)处"Warning: integer constant is too large for ‘long’ type"
运行(2)时显示0x33334444
即使把long long换成int64_t或者long long int也不行，到底怎样才能使用64位整数呢？

C/C++ code

/*-

 * file: int64.c

 * auth: mymtom

 * date: 2008-08-19

 */
#include <sys/types.h>

#include <stdio.h>
int

main(void)

{

        long long       nLL = 0x1111222233334444LL;

        int64_t         n64 = 0x5555666677778888LL;
        (void)printf("%llx\n", nLL);

        (void)printf("%llx\n", n64);
        return (0);

}



你用的就是64位，只不过你当32为打印出来。
要去掉warning:
man gcc
      -Wlong-long
          Warn if long long type is used.  This is default.  To inhibit the
          warning messages, use -Wno-long-long.  Flags -Wlong-long and
          -Wno-long-long are taken into account only when -pedantic flag is
          used.